What is the asymptotes of f(x)=(x^3-1)/(x^2-5x+4) ?

The asymptotes of f(x)=(x^3-1)/(x^2-5x+4) is Vertical: x=4,Slant: y=x+5

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asymptotes of f(x)=(x^3-1)/(x^2-5x+4)

asymptotes

f (x) = \frac{x ^{3} - 1}{x ^{2} - 5 x + 4}

Vertical : x = 4, Slant : y = x + 5

Solution steps

Vertical asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 5 x + 4} : x = 4

Horizontal Asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 5 x + 4} :

None

Slant Asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 5 x + 4} : y = x + 5

Vertical : x = 4, Slant : y = x + 5

f (x) = x^{5} + 1

f (x) = 2 x - 3 y = - 6

f (- 4) = - x, x < 0

f (x) = x 5 - x^{2}

y = \frac{1}{2} x + 3, (1, 2)

What is the asymptotes of f(x)=(x^3-1)/(x^2-5x+4) ?
The asymptotes of f(x)=(x^3-1)/(x^2-5x+4) is Vertical: x=4,Slant: y=x+5