What is the domain of f(x)= 1/(sqrt(9-t^2)) ?

The domain of f(x)= 1/(sqrt(9-t^2)) is -3<t<3

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domain of f(x)= 1/(sqrt(9-t^2))

domain

- 3 < t < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq t \leq 3

Find undefined (singularity) points:

t = 3, t = - 3

Combine real regions and undefined points for final function domain

- 3 < t < 3

What is the domain of f(x)= 1/(sqrt(9-t^2)) ?
The domain of f(x)= 1/(sqrt(9-t^2)) is -3<t<3