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Popular >

range of x^2+8x+6

Solution

range

x^{2} + 8 x + 6

Solution

f (x) \geq - 10

+1

Solution steps

Vertex of

x^{2} + 8 x + 6 :

Minimum

(- 4, - 10)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 4, - 10)

f (x) \geq - 10

Popular Examples

domain of f(x)=(x^4)/(x^2+x-56)domain

f (x) = \frac{x ^{4}}{x ^{2} + x - 56}

slope ofintercept y-10=12(x-6)slope intercept

y - 10 = 12 (x - 6)

domain of f(x)=-x/(5-2x)domain

f (x) = - \frac{x}{5 - 2 x}

range of y=2e^x+1 range

y = 2 e^{x} + 1

y = x + 3

Frequently Asked Questions (FAQ)

What is the range of x^2+8x+6 ?
The range of x^2+8x+6 is f(x)>=-10