What is the domain of f(x)=sqrt(x(4-x)) ?

The domain of f(x)=sqrt(x(4-x)) is 0<= x<= 4

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domain of f(x)=sqrt(x(4-x))

domain

f (x) = x (4 - x)

0 \leq x \leq 4

Interval Notation

[0, 4]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 4

The function domain

0 \leq x \leq 4

e x t re m e ln (2 - 5 x^{2})

in t erce pt s f (4) = - 2 x^{2} + 4 x + 8

in f l ec t i o n f (x) = \frac{1}{3 x ^{2} + 8}

cr i t i c a l f (x) = \frac{5}{x ^{2} - 49}

in f l ec t i o n f (x) = 2 x^{3} - 3 x^{2} + 7 x - 4

What is the domain of f(x)=sqrt(x(4-x)) ?
The domain of f(x)=sqrt(x(4-x)) is 0<= x<= 4