What is the asymptotes of f(x)=(x^2-4x)/(x^2-16) ?

The asymptotes of f(x)=(x^2-4x)/(x^2-16) is Vertical: x=-4,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-4x)/(x^2-16)

asymptotes

f (x) = \frac{x ^{2} - 4 x}{x ^{2} - 16}

Vertical : x = - 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} : x = - 4

Horizontal Asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} :

None

Vertical : x = - 4, Horizontal : y = 1

3 x + 24

f (x) = 4 x^{2} - 6 x^{4}

f (x) = - 40 - 8 x - 4

f (x) = (x + 2)^{3} (x - 4)^{4}

y = x - 1

What is the asymptotes of f(x)=(x^2-4x)/(x^2-16) ?
The asymptotes of f(x)=(x^2-4x)/(x^2-16) is Vertical: x=-4,Horizontal: y=1