What is the extreme f(x)=3x^3-36x-6 ?

The extreme f(x)=3x^3-36x-6 is Maximum(-2,42),Minimum(2,-54)

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extreme f(x)=3x^3-36x-6

extreme points

f (x) = 3 x^{3} - 36 x - 6

Maximum (- 2, 42), Minimum (2, - 54)

Solution steps

f^{'} (x) = 9 x^{2} - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

3 x^{3} - 36 x - 6 : 42

Maximum (- 2, 42)

Plug

x = 2

into

3 x^{3} - 36 x - 6 : - 54

Minimum (2, - 54)

Maximum (- 2, 42), Minimum (2, - 54)

f (x) = sin^{2} (2 x)

f (x) = x - 4

f (x) = 6 - 5 x^{2}

x 4 - x^{2}

f (x) = (t^{2} - 36)^{\frac{1}{3}}

What is the extreme f(x)=3x^3-36x-6 ?
The extreme f(x)=3x^3-36x-6 is Maximum(-2,42),Minimum(2,-54)