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Popular >

midpoint (2,-2),(-1,4)

Solution

midpoint

(2, - 2), (- 1, 4)

Solution

(\frac{1}{2}, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 2), (x_{2}, y_{2}) = (- 1, 4)

= (\frac{- 1 + 2}{2}, \frac{4 - 2}{2})

Refine

= (\frac{1}{2}, 1)

Popular Examples

inverse of f(x)=((x-2))/((4x+6))inverse

f (x) = \frac{( x - 2 )}{( 4 x + 6 )}

extreme s/(s^2+4s+5)extreme points

\frac{s}{s ^{2} + 4 s + 5}

critical f(x)= x/(x^2-x+1)critical points

f (x) = \frac{x}{x ^{2} - x + 1}

inverse of f(x)=sec(1/x)inverse

f (x) = sec (\frac{1}{x})

symmetry x^5+3x^4-25x^3-79x^2+100 symmetry

x^{5} + 3 x^{4} - 25 x^{3} - 79 x^{2} + 100

Frequently Asked Questions (FAQ)

What is the midpoint (2,-2),(-1,4) ?
The midpoint (2,-2),(-1,4) is (1/2 ,1)