What is the critical f(x)=(x^2)/(4x-3) ?

The critical f(x)=(x^2)/(4x-3) is x=0,x= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)=(x^2)/(4x-3)

critical points

f (x) = \frac{x ^{2}}{4 x - 3}

x = 0, x = \frac{3}{2}

Solution steps

\frac{x ^{2}}{4 x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{3}{2}, x = \frac{3}{4}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{4 x - 3} : x < \frac{3}{4} or x > \frac{3}{4}

\frac{x ^{2}}{4 x - 3}

is not defined at

x = \frac{3}{4}

, therefore:

x = 0, x = \frac{3}{2}

a sy m pt o t es f (x) = 4 x^{3} - 9 x^{2} + 6 x

m o n o t o n e \frac{x + 8}{x + 1}

a sy m pt o t es f (x) = \frac{x + 8}{x}

in v erse f (x) = - \frac{9}{2} x^{5}

p er p e n d i c u l a r y = - 2 x + 6, (1, 6)

What is the critical f(x)=(x^2)/(4x-3) ?
The critical f(x)=(x^2)/(4x-3) is x=0,x= 3/2