What is the extreme f(x)=x^3-6x^2-36x ?

The extreme f(x)=x^3-6x^2-36x is Maximum(-2,40),Minimum(6,-216)

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extreme f(x)=x^3-6x^2-36x

extreme points

f (x) = x^{3} - 6 x^{2} - 36 x

Maximum (- 2, 40), Minimum (6, - 216)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 2

into

x^{3} - 6 x^{2} - 36 x : 40

Maximum (- 2, 40)

Plug

x = 6

into

x^{3} - 6 x^{2} - 36 x : - 216

Minimum (6, - 216)

Maximum (- 2, 40), Minimum (6, - 216)

in v erse \frac{2}{5 x + 8}

d o main f (x) = \frac{1}{1 - sin ( x )}

e x t re m e f (x) = x^{3} - 75 x + 3

s l o p e in t erce pt y + 4 = (- \frac{7}{8}) (x - 7)

d o main 2 x^{2} + x - 8

What is the extreme f(x)=x^3-6x^2-36x ?
The extreme f(x)=x^3-6x^2-36x is Maximum(-2,40),Minimum(6,-216)