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Popular >

distance (5,3),(7,-4)

Solution

distance

(5, 3), (7, - 4)

Solution

53

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, 3)

and

(7, - 4)

is

= (7 - 5)^{2} + (- 4 - 3)^{2}

Simplify

= 53

Popular Examples

extreme f(x)=3cos(x)-4sin(x)extreme points

f (x) = 3 cos (x) - 4 sin (x)

domain of e^x domain

e^{x}

symmetry x^2-2x symmetry

x^{2} - 2 x

domain of (sqrt(x^2-1))(1/(x+2))domain

(x^{2} - 1) (\frac{1}{x + 2})

slope ofintercept y-3= 6/5 (x-5)slope intercept

y - 3 = \frac{6}{5} (x - 5)

Frequently Asked Questions (FAQ)

What is the distance (5,3),(7,-4) ?
The distance (5,3),(7,-4) is square root of 53