What is the inverse of f(x)=(4x-5)^2 ?

The inverse of f(x)=(4x-5)^2 is (sqrt(x)+5)/4 ,(-sqrt(x)+5)/4

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inverse of f(x)=(4x-5)^2

inverse

f (x) = (4 x - 5)^{2}

\frac{x + 5}{4}, \frac{- x + 5}{4}

Solution steps

y = (4 x - 5)^{2}

Replace

x

with

y

x = (4 y - 5)^{2}

Solve for

y, x = (4 y - 5)^{2}

\frac{x + 5}{4}, \frac{- x + 5}{4}

in v erse - 2 x + 4

r an g e f (x) = 5 x - 4

r an g e f (x) = 2 x - 5

in t erce pt s f (x) = x^{2} - 5 x - 6

d o main f (x) = 36 - x^{2} + x^{2} - 25

What is the inverse of f(x)=(4x-5)^2 ?
The inverse of f(x)=(4x-5)^2 is (sqrt(x)+5)/4 ,(-sqrt(x)+5)/4