What is the range of f(x)= 2/(x+1) ?

The range of f(x)= 2/(x+1) is f(x) 0

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range of f(x)= 2/(x+1)

range

f (x) = \frac{2}{x + 1}

f (x) < 0 or f (x) > 0

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{2}{x + 1}

Inverse of

\frac{2}{x + 1} : \frac{2}{x} - 1

\frac{2}{x} - 1

Find the domain of each inverse function

Domain of

\frac{2}{x} - 1 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

f (x) = \frac{3 x}{x + 3}

f (x) = ∣ x ∣ + 4

\frac{3 x + 4}{x ^{2} - 25}

f (x) = 3 y - x = 3

f (x) = \frac{3 x ^{2} - 5 x - 2}{x ^{2} - 4}

What is the range of f(x)= 2/(x+1) ?
The range of f(x)= 2/(x+1) is f(x)<0\lor f(x)>0