What is the inverse of y=0.5x^2+2 ?

The inverse of y=0.5x^2+2 is sqrt(2)sqrt(x-2),-sqrt(2)sqrt(x-2)

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inverse of y=0.5x^2+2

inverse

y = 0.5 x^{2} + 2

2 x - 2, - 2 x - 2

Solution steps

y = 0.5 x^{2} + 2

Replace

x

with

y

x = 0.5 y^{2} + 2

Solve for

y, x = 0.5 y^{2} + 2

2 x - 2, - 2 x - 2

s l o p e in t erce pt - 8 y = - 7 x + 20

d o main f (x) = 8 (\frac{x}{2}) - 7

s hi f t sec (2 x - 3 π)

r an g e f (x) = ln (x - 2)

d o main f (x) = ln (16 - t^{2})

What is the inverse of y=0.5x^2+2 ?
The inverse of y=0.5x^2+2 is sqrt(2)sqrt(x-2),-sqrt(2)sqrt(x-2)