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Popular Functions >

range of 2x^2+15x+7

Solution

range

2 x^{2} + 15 x + 7

Solution

f (x) \geq - \frac{169}{8}

+1

Interval Notation

[- \frac{169}{8}, \infty)

Solution steps

Vertex of

2 x^{2} + 15 x + 7 :

Minimum

(- \frac{15}{4}, - \frac{169}{8})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- \frac{15}{4}, - \frac{169}{8})

f (x) \geq - \frac{169}{8}

Graph

Popular Examples

domain of f(x)= 7/x+9/(x+9)

d o main f (x) = \frac{7}{x} + \frac{9}{x + 9}

range of f(x)=|x^2-4|+3

r an g e f (x) = x^{2} - 4 + 3

intercepts of f(x)=-3x-4=-5y-8

in t erce pt s f (x) = - 3 x - 4 = - 5 y - 8

symmetry (x^5-x)/(x^2+1)

sy mm e t ry \frac{x ^{5} - x}{x ^{2} + 1}

domain of f(x)=x^2-15

d o main f (x) = x^{2} - 15

Frequently Asked Questions (FAQ)

What is the range of 2x^2+15x+7 ?
The range of 2x^2+15x+7 is f(x)>=-169/8