What is the asymptotes of f(x)=(2x)/(sqrt(9x^2+1)) ?

The asymptotes of f(x)=(2x)/(sqrt(9x^2+1)) is Horizontal: y= 2/3 ,y=-2/3

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asymptotes of f(x)=(2x)/(sqrt(9x^2+1))

asymptotes

f (x) = \frac{2 x}{9 x ^{2} + 1}

Horizontal : y = \frac{2}{3}, y = - \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{2 x}{9 x ^{2} + 1} :

None

Horizontal Asymptotes of

\frac{2 x}{9 x ^{2} + 1} : y = \frac{2}{3}, y = - \frac{2}{3}

Slant Asymptotes of

\frac{2 x}{9 x ^{2} + 1} :

None

Horizontal : y = \frac{2}{3}, y = - \frac{2}{3}

\frac{7 x}{x ^{2} + 10}

f (x) = 7 x ln (x)

f (x) = 2 x + 1 - x + 1

f (x) = 2 x + y = 1

r (t) = \frac{2 t ^{2}}{1 - t ^{2}} \frac{t + 1}{t}

What is the asymptotes of f(x)=(2x)/(sqrt(9x^2+1)) ?
The asymptotes of f(x)=(2x)/(sqrt(9x^2+1)) is Horizontal: y= 2/3 ,y=-2/3