What is the inverse of f(x)=\sqrt[5]{x-8}+1 ?

The inverse of f(x)=\sqrt[5]{x-8}+1 is x^5-5x^4+10x^3-10x^2+5x+7

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inverse of f(x)=\sqrt[5]{x-8}+1

inverse

f (x) = 5 x - 8 + 1

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x + 7

Solution steps

y = 5 x - 8 + 1

Replace

x

with

y

x = 5 y - 8 + 1

Solve for

y, x = 5 y - 8 + 1

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x + 7

r an g e f (x) = \frac{x + 1}{x - 4}

p a r a ll e l y = x + 3

in t erce pt s f (x) = \frac{5}{x + 1}

y = x^{2} - 5

l in e (4, 5), (12, 6)

What is the inverse of f(x)=\sqrt[5]{x-8}+1 ?
The inverse of f(x)=\sqrt[5]{x-8}+1 is x^5-5x^4+10x^3-10x^2+5x+7