What is the perpendicular 2= 7/5 (-5)+b ?

The perpendicular 2= 7/5 (-5)+b is y=c

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perpendicular 2= 7/5 (-5)+b

perpendicular

2 = \frac{7}{5} (- 5) + b

y = c

Solution steps

Find the slope of

2 = \frac{7}{5} (- 5) + b : m = \infty

Compute the slope of the perpendicular line:

m_{p} = 0

Line with slope m=

0 : y = c

y = c

a sy m pt o t es \frac{x ^{2} + 2 x - 15}{x - 4}

in v erse f (x) = - \frac{21}{41} ln (4100 x - 20601)

d o main f (x) = 4 x^{2} - 5 x + 8

s l o p e 6 x + 10 y = 8

d o main f (x) = x \cdot x

What is the perpendicular 2= 7/5 (-5)+b ?
The perpendicular 2= 7/5 (-5)+b is y=c