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Popular >

midpoint (2,-2),(5,1)

Solution

midpoint

(2, - 2), (5, 1)

Solution

(\frac{7}{2}, - \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 2), (x_{2}, y_{2}) = (5, 1)

= (\frac{5 + 2}{2}, \frac{1 - 2}{2})

Refine

= (\frac{7}{2}, - \frac{1}{2})

Popular Examples

domain of (4x+4)/(x^2+3x+2)domain

\frac{4 x + 4}{x ^{2} + 3 x + 2}

amplitude of f(x)=0.5cos(6x)amplitude

f (x) = 0.5 cos (6 x)

range of f(x)=sqrt(x^2-3x)range

f (x) = x^{2} - 3 x

domain of f(x)=cot(x)domain

f (x) = cot (x)

inverse of f(x)=(x-3)/2 inverse

f (x) = \frac{x - 3}{2}

Frequently Asked Questions (FAQ)

What is the midpoint (2,-2),(5,1) ?
The midpoint (2,-2),(5,1) is (7/2 ,-1/2)