What is the inverse of f(x)=2(x+3)^3+1 ?

The inverse of f(x)=2(x+3)^3+1 is \sqrt[3]{(x-1)/2}-3

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inverse of f(x)=2(x+3)^3+1

inverse

f (x) = 2 (x + 3)^{3} + 1

3 \frac{x - 1}{2} - 3

Solution steps

y = 2 (x + 3)^{3} + 1

Replace

x

with

y

x = 2 (y + 3)^{3} + 1

Solve for

y, x = 2 (y + 3)^{3} + 1

3 \frac{x - 1}{2} - 3

am pl i t u d e f (t) = 2 sin (t + 3) + 1

in v erse 3 e^{- 2 x}

in v erse f (x) = \frac{( 4 x - 4 )}{3 x - 3}

d i s t an ce (- 7, 5), (- 1, - 2)

s l o p e in t erce pt 4 x + 4 y = 16

What is the inverse of f(x)=2(x+3)^3+1 ?
The inverse of f(x)=2(x+3)^3+1 is \sqrt[3]{(x-1)/2}-3