What is the extreme f(x)=(x-2)(x-5)^3+9 ?

The extreme f(x)=(x-2)(x-5)^3+9 is Minimum(11/4 , 117/256),Saddle(5,9)

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extreme f(x)=(x-2)(x-5)^3+9

extreme points

f (x) = (x - 2) (x - 5)^{3} + 9

Minimum (\frac{11}{4}, \frac{117}{256}), Saddle (5, 9)

Solution steps

f^{'} (x) = 4 x^{3} - 51 x^{2} + 210 x - 275

Find intervals:

Decreasing

: - \infty < x < \frac{11}{4},

Increasing

: \frac{11}{4} < x < 5,

Increasing

: 5 < x < \infty

Plug

x = \frac{11}{4}

into

(x - 2) (x - 5)^{3} + 9 : \frac{117}{256}

Minimum (\frac{11}{4}, \frac{117}{256})

Plug

x = 5

into

(x - 2) (x - 5)^{3} + 9 : 9

Saddle (5, 9)

Minimum (\frac{11}{4}, \frac{117}{256}), Saddle (5, 9)

4 x + 6

f (x) = \frac{x}{2} + 3

f (x) = (\frac{10}{9})^{- x}

\frac{e ^{3 x}}{sin ( 5 x )}

y = x^{2} - 16

What is the extreme f(x)=(x-2)(x-5)^3+9 ?
The extreme f(x)=(x-2)(x-5)^3+9 is Minimum(11/4 , 117/256),Saddle(5,9)