What is the extreme f(x)=x^3+6x^2-15x ?

The extreme f(x)=x^3+6x^2-15x is Maximum(-5,100),Minimum(1,-8)

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extreme f(x)=x^3+6x^2-15x

extreme points

f (x) = x^{3} + 6 x^{2} - 15 x

Maximum (- 5, 100), Minimum (1, - 8)

Solution steps

f^{'} (x) = 3 x^{2} + 12 x - 15

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 5

into

x^{3} + 6 x^{2} - 15 x : 100

Maximum (- 5, 100)

Plug

x = 1

into

x^{3} + 6 x^{2} - 15 x : - 8

Minimum (1, - 8)

Maximum (- 5, 100), Minimum (1, - 8)

f (x) = \frac{2}{x - 6}

f (x) = 4 x^{3} - 54 x^{2} + 180

(1.6) (- 2.8)

f (x) = \frac{x + 1}{x + 5}

f (x) = x - 3 x^{\frac{1}{3}}

What is the extreme f(x)=x^3+6x^2-15x ?
The extreme f(x)=x^3+6x^2-15x is Maximum(-5,100),Minimum(1,-8)