What is the inverse of f(x)=2+1/3 (x-5)^2 ?

The inverse of f(x)=2+1/3 (x-5)^2 is sqrt(3x-6)+5,-sqrt(3x-6)+5

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inverse of f(x)=2+1/3 (x-5)^2

inverse

f (x) = 2 + \frac{1}{3} (x - 5)^{2}

3 x - 6 + 5, - 3 x - 6 + 5

Solution steps

y = 2 + \frac{1}{3} (x - 5)^{2}

Replace

x

with

y

x = 2 + \frac{1}{3} (y - 5)^{2}

Solve for

y, x = 2 + \frac{1}{3} (y - 5)^{2}

3 x - 6 + 5, - 3 x - 6 + 5

am pl i t u d e \frac{1}{2} cos (2 x)

in t erce pt s \frac{x ^{2} - 2 x - 24}{x - 8}

s l o p e in t erce pt - x + y = 14

d o main f (x) = 2 sin (4 x)

d o main f (x) = lo g_{3} (x - 8)

What is the inverse of f(x)=2+1/3 (x-5)^2 ?
The inverse of f(x)=2+1/3 (x-5)^2 is sqrt(3x-6)+5,-sqrt(3x-6)+5