What is the perpendicular 4x+3y=12 ?

The perpendicular 4x+3y=12 is y= 3/4 x+b

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perpendicular 4x+3y=12

perpendicular

4 x + 3 y = 12

y = \frac{3}{4} x + b

Solution steps

Find the slope of

4 x + 3 y = 12 : m = - \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{4}

Line with slope m=

\frac{3}{4} : y = \frac{3}{4} x + b

y = \frac{3}{4} x + b

d o main f (x) = \frac{6}{x - 5}

l in e (3, 3), (4, 0)

d o main f (x) = 2 - - 4 - 3 x

r an g e arccos (x - 1) + \frac{π}{2}

e x t re m e f (x) = x^{4} - 8 x^{3} + 7