What is the domain of f(x)=(x^2+9)/(x^2-2x-1) ?

The domain of f(x)=(x^2+9)/(x^2-2x-1) is x 1+sqrt(2)

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domain of f(x)=(x^2+9)/(x^2-2x-1)

domain

f (x) = \frac{x ^{2} + 9}{x ^{2} - 2 x - 1}

x < 1 - 2 or 1 - 2 < x < 1 + 2 or x > 1 + 2

Interval Notation

(- \infty, 1 - 2) \cup (1 - 2, 1 + 2) \cup (1 + 2, \infty)

Solution steps

Find undefined (singularity) points:

x = 1 + 2, x = 1 - 2

The function domain

x < 1 - 2 or 1 - 2 < x < 1 + 2 or x > 1 + 2

in t erce pt s f (x) = 3 x + 2 y = 6

in v erse f (x) = \frac{x + 3}{4}

in v erse f (x) = 4 x^{2} - 1, x \leq 0

in v erse f (x) = \frac{1}{2 x - 1}

e x t re m e f (x) = \frac{2}{x}

What is the domain of f(x)=(x^2+9)/(x^2-2x-1) ?
The domain of f(x)=(x^2+9)/(x^2-2x-1) is x<1-sqrt(2)\lor 1-sqrt(2)<x<1+sqrt(2)\lor x>1+sqrt(2)