What is the domain of f(x)=sqrt(t+6) ?

The domain of f(x)=sqrt(t+6) is t>=-6

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domain of f(x)=sqrt(t+6)

domain

f (x) = t + 6

t \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 6

The function domain

t \geq - 6

in f l ec t i o n - \frac{36 ( x - 1 )}{( x + 3 ) ^{3}}

in v erse f (x) = 7 x - 6

s im pl i f y (1) (0.2)

in t erce pt s f (x) = 15 cos (\frac{1}{2}) (x + \frac{π}{2})

e x t re m e f (x) = - x^{3} - x^{2} + 5 x - 1