What is the domain of 3/(sqrt(9-x^2)) ?

The domain of 3/(sqrt(9-x^2)) is -3<x<3

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domain of 3/(sqrt(9-x^2))

domain

\frac{3}{9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

s l o p e 8 x + 9 y = 18

d o main 4 x - 2 - 1

mi d p o in t (3, - 4), (5, 4)

in v erse f (x) = \frac{x ^{\frac{1}{3}}}{3}

in v erse ln (8 t)