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midpoint
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domain of (x-2)/(x^2+49)simplify (-3.5)(3.5)extreme f(x)=(x^3+x-2)/(x-x^2)symmetry x^2+y=1extreme (x-3)sqrt(x)
Frequently Asked Questions (FAQ)
What is the midpoint (-10,2),(0,-7) ?
The midpoint (-10,2),(0,-7) is (-5,-5/2)