What is the slope ofintercept 3x+y-2=0 ?

The slope ofintercept 3x+y-2=0 is y=-3x+2

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slope ofintercept 3x+y-2=0

slope intercept

3 x + y - 2 = 0

y = - 3 x + 2

Solution steps

3 x + y - 2 = 0

Convert to slope intercept form:

y = - 3 x + 2

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - 3 x + 2

f (x) = \frac{1}{2} - \frac{1}{2} cos (2 x - \frac{π}{4})

f (x) = \frac{x}{x ^{2} - 3 x + 2}

f (x) = \frac{( 2 x + 4 )}{( x ^{2} - 16 )}

\frac{X ^{2} + 3 X - 4}{X ^{4} - X ^{3} + X ^{2} - X}

x - 3 + \frac{2}{x + 1}

What is the slope ofintercept 3x+y-2=0 ?
The slope ofintercept 3x+y-2=0 is y=-3x+2