What is the inverse of f(x)=((x+20))/(x-16) ?

The inverse of f(x)=((x+20))/(x-16) is (20+16x)/(x-1)

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inverse of f(x)=((x+20))/(x-16)

inverse

f (x) = \frac{( x + 20 )}{x - 16}

\frac{20 + 16 x}{x - 1}

Solution steps

y = \frac{x + 20}{x - 16}

Replace

x

with

y

x = \frac{y + 20}{y - 16}

Solve for

y, x = \frac{y + 20}{y - 16}

\frac{20 + 16 x}{x - 1}

d o main f (x) = \frac{- 1}{2 7 - x}

in v erse f (x) = \frac{1}{x - 3} + 1

in v erse f (x) = 6 x - 9

in v erse f (x) = e^{x}

d o main f (x) = \frac{1}{2} 4 + x^{2}

What is the inverse of f(x)=((x+20))/(x-16) ?
The inverse of f(x)=((x+20))/(x-16) is (20+16x)/(x-1)