What is the critical-5x^4-x^3+2x^2 ?

The critical-5x^4-x^3+2x^2 is x=(-3-sqrt(329))/(40),x=0,x=(-3+sqrt(329))/(40)

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critical-5x^4-x^3+2x^2

critical points

- 5 x^{4} - x^{3} + 2 x^{2}

x = \frac{- 3 - 329}{40}, x = 0, x = \frac{- 3 + 329}{40}

Solution steps

- 5 x^{4} - x^{3} + 2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{- 3 - 329}{40}, x = 0, x = \frac{- 3 + 329}{40}

Identify critical points not in

f (x)

domain

Domain of

- 5 x^{4} - x^{3} + 2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{- 3 - 329}{40}, x = 0, x = \frac{- 3 + 329}{40}

f (x) = x - \frac{1}{18}

f (x) = \frac{1}{x + 12}

f (x) = \frac{1}{3} x - 3

\frac{5 x}{x ^{2} - 3 x - 4}

\frac{( 2 x + x ) ^{2}}{5 + x x}

What is the critical-5x^4-x^3+2x^2 ?
The critical-5x^4-x^3+2x^2 is x=(-3-sqrt(329))/(40),x=0,x=(-3+sqrt(329))/(40)