What is the critical f(x)=x^3+7x^2-3x+9 ?

The critical f(x)=x^3+7x^2-3x+9 is x=-(7+sqrt(58))/3 ,x=(-7+sqrt(58))/3

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critical f(x)=x^3+7x^2-3x+9

critical points

f (x) = x^{3} + 7 x^{2} - 3 x + 9

x = - \frac{7 + 58}{3}, x = \frac{- 7 + 58}{3}

Solution steps

x^{3} + 7 x^{2} - 3 x + 9

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{7 + 58}{3}, x = \frac{- 7 + 58}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 7 x^{2} - 3 x + 9 : - \infty < x < \infty

All critical points are in domain

x = - \frac{7 + 58}{3}, x = \frac{- 7 + 58}{3}

x^{3} - 27

(x + 1)^{2}

y = \frac{x - 2}{x + 2}

f (x) = \frac{x ^{2} + 4}{4 x - 4}

f (x) = \frac{- 2 x ^{2} + 1}{x ^{2} + x + 8}

What is the critical f(x)=x^3+7x^2-3x+9 ?
The critical f(x)=x^3+7x^2-3x+9 is x=-(7+sqrt(58))/3 ,x=(-7+sqrt(58))/3