What is the perpendicular y=-1/2 x-1,(3,2) ?

The perpendicular y=-1/2 x-1,(3,2) is y=2x-4

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perpendicular y=-1/2 x-1,(3,2)

perpendicular

y = - \frac{1}{2} x - 1, (3, 2)

y = 2 x - 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{1}{2} x - 1

that passes through

(3, 2)

Find the slope of

y = - \frac{1}{2} x - 1 : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Find the line with slope m=

2

and passing through

(3, 2) : y = 2 x - 4

y = 2 x - 4

f (x) = \frac{1}{3} x - 5

3 x^{3}

\frac{4 x}{x ^{2} + 4}

\frac{2 x + 1}{4 x ^{3} + 5 x + 7}

What is the perpendicular y=-1/2 x-1,(3,2) ?
The perpendicular y=-1/2 x-1,(3,2) is y=2x-4