What is the perpendicular y+3= 3/4 x+5 ?

The perpendicular y+3= 3/4 x+5 is y=-4/3 x+b

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perpendicular y+3= 3/4 x+5

perpendicular

y + 3 = \frac{3}{4} x + 5

y = - \frac{4}{3} x + b

Solution steps

Find the slope of

y + 3 = \frac{3}{4} x + 5 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Line with slope m=

- \frac{4}{3} : y = - \frac{4}{3} x + b

y = - \frac{4}{3} x + b

in t erce pt s f (x) = ln (x) + 6

r an g e \frac{3}{( 2 x - 5 )}

s im pl i f y (3.5) (2.6)

d o main f (x) = 5 - x^{2}

s im pl i f y (- 4.3) (5.7)

What is the perpendicular y+3= 3/4 x+5 ?
The perpendicular y+3= 3/4 x+5 is y=-4/3 x+b