What is the line (150,149.2),(165,163.5) ?

The line (150,149.2),(165,163.5) is y=0.95333…x+6.2

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line (150,149.2),(165,163.5)

line

(150, 149.2), (165, 163.5)

y = 0.95333 \dots x + 6.2

Solution steps

Find the line

y = mx + b

passing through

(150, 149.2)

(165, 163.5)

Compute the slope

(150, 149.2), (165, 163.5) : m = 0.95333 \dots

Compute the

y

intercept:

b = 6.2

Construct the line equation

y = mx + b

where

m = 0.95333 \dots

and

b = 6.2

y = 0.95333 \dots x + 6.2

f (x) = \frac{1}{2} x - \frac{1}{10}

f (x) = (x + 2)^{3}

y = x^{2} + 5

\frac{x}{x ^{2} - x + 1}

y = 3 - \frac{1}{4} x

What is the line (150,149.2),(165,163.5) ?
The line (150,149.2),(165,163.5) is y=0.95333…x+6.2