What is the perpendicular y=3x-2,\at x=-1 ?

The perpendicular y=3x-2,\at x=-1 is y=-1/3 x-16/3

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perpendicular y=3x-2,\at x=-1

perpendicular

y = 3 x - 2, at x = - 1

y = - \frac{1}{3} x - \frac{16}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

x = - 1

Find the perpendicular point:

(- 1, - 5)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 1, - 5) : y = - \frac{1}{3} x - \frac{16}{3}

y = - \frac{1}{3} x - \frac{16}{3}

e x t re m e f (x) = sin (5 t)

p er p e n d i c u l a r y = - \frac{2}{5}, (- 2, 1)

a sy m pt o t es f (x) = \frac{4 - x}{x - 16}

s l o p e y + 3 = x

in v erse f (x) = 2 - 4 - x

What is the perpendicular y=3x-2,\at x=-1 ?
The perpendicular y=3x-2,\at x=-1 is y=-1/3 x-16/3