What is the inverse of f(x)=1+e^{1-\sqrt[3]{x}} ?

The inverse of f(x)=1+e^{1-\sqrt[3]{x}} is -ln^3(x-1)+3ln^2(x-1)-3ln(x-1)+1

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inverse of f(x)=1+e^{1-\sqrt[3]{x}}

inverse

- ln^{3} (x - 1) + 3 ln^{2} (x - 1) - 3 ln (x - 1) + 1

Solution steps

Replace

x

with

y

Solve for

- ln^{3} (x - 1) + 3 ln^{2} (x - 1) - 3 ln (x - 1) + 1

(1.6) (3.2)

(10.2) (40.1)

f (x) = \frac{1}{x ^{2} - 9}

f (x) = 2 x^{2} - \frac{1}{x}

\frac{8 - x ^{3}}{2 x ^{2}}

What is the inverse of f(x)=1+e^{1-\sqrt[3]{x}} ?
The inverse of f(x)=1+e^{1-\sqrt[3]{x}} is -ln^3(x-1)+3ln^2(x-1)-3ln(x-1)+1