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Popular >

midpoint (2,-3),(10,7)

Solution

midpoint

(2, - 3), (10, 7)

Solution

(6, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 3), (x_{2}, y_{2}) = (10, 7)

= (\frac{10 + 2}{2}, \frac{7 - 3}{2})

Refine

= (6, 2)

Popular Examples

extreme f(x)=-7+6x-x^3 extreme points

f (x) = - 7 + 6 x - x^{3}

domain of f(x)= 2/(6-5x)domain

f (x) = \frac{2}{6 - 5 x}

parity f(x)=x^3-3 parity

f (x) = x^{3} - 3

asymptotes of-4/(5/x-5)asymptotes

- \frac{4}{\frac{5}{x} - 5}

critical x^3-6x^2+9x+1 critical points

x^{3} - 6 x^{2} + 9 x + 1

Frequently Asked Questions (FAQ)

What is the midpoint (2,-3),(10,7) ?
The midpoint (2,-3),(10,7) is (6,2)