What is the critical x^5-5x ?

The critical x^5-5x is x=-1,x=1

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critical x^5-5x

critical points

x^{5} - 5 x

x = - 1, x = 1

Solution steps

x^{5} - 5 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{5} - 5 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

\frac{( x + 3 ) ( x - 3 )}{x ^{2} + 9}

cos (\frac{x}{4} + \frac{π}{4}) - 2

f (x) = \frac{2 x ^{2} - x - 7}{x ^{2} + 4}

f (x) = 1 - (x - 4)^{2}