What is the inverse of f(t)=100(1-t/(50))^2 ?

The inverse of f(t)=100(1-t/(50))^2 is -5sqrt(t)+50,5sqrt(t)+50

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inverse of f(t)=100(1-t/(50))^2

inverse

f (t) = 100 (1 - \frac{t}{50})^{2}

- 5 t + 50, 5 t + 50

Solution steps

y = 100 (1 - \frac{t}{50})^{2}

Replace

t

with

y

t = 100 (1 - \frac{y}{50})^{2}

Solve for

y, t = 100 (1 - \frac{y}{50})^{2}

- 5 t + 50, 5 t + 50

\frac{5}{x - 6}

\frac{1}{x - 5}

(- 8, 12), (- 13, - 2)

f (x) = \frac{x + 6}{x - 4}

\frac{1}{x - 1}

What is the inverse of f(t)=100(1-t/(50))^2 ?
The inverse of f(t)=100(1-t/(50))^2 is -5sqrt(t)+50,5sqrt(t)+50