What is the domain of tan(2θ-(11pi)/6)-1 ?

The domain of tan(2θ-(11pi)/6)-1 is pi/2 n<= θ< pi/6+pi/2 n\lor pi/6+pi/2 n<θ< pi/2+pi/2 n

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domain of tan(2θ-(11pi)/6)-1

domain

tan (2 θ - \frac{11 π}{6}) - 1

\frac{π}{2} n \leq θ < \frac{π}{6} + \frac{π}{2} n or \frac{π}{6} + \frac{π}{2} n < θ < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{6} + \frac{π}{2} n) \cup (\frac{π}{6} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

tan (2 θ - \frac{11 π}{6}) - 1

and compare to zero:

θ = \frac{π}{6} + \frac{π}{2} n

Periodicity of

tan (2 θ - \frac{11 π}{6}) - 1 : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq θ < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq θ < \frac{π}{6} + \frac{π}{2} n or \frac{π}{6} + \frac{π}{2} n < θ < \frac{π}{2} + \frac{π}{2} n

What is the domain of tan(2θ-(11pi)/6)-1 ?
The domain of tan(2θ-(11pi)/6)-1 is pi/2 n<= θ< pi/6+pi/2 n\lor pi/6+pi/2 n<θ< pi/2+pi/2 n