What is the critical f(x)=x^4-162x^2+6561 ?

The critical f(x)=x^4-162x^2+6561 is x=-9,x=0,x=9

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critical f(x)=x^4-162x^2+6561

critical points

f (x) = x^{4} - 162 x^{2} + 6561

x = - 9, x = 0, x = 9

Solution steps

x^{4} - 162 x^{2} + 6561

Find where

f^{'} (x)

is equal to zero or undefined

x = - 9, x = 0, x = 9

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 162 x^{2} + 6561 : - \infty < x < \infty

All critical points are in domain

x = - 9, x = 0, x = 9

What is the critical f(x)=x^4-162x^2+6561 ?
The critical f(x)=x^4-162x^2+6561 is x=-9,x=0,x=9