What is the inverse of f(x)=log_{6}(x+2)-log_{6}(2) ?

The inverse of f(x)=log_{6}(x+2)-log_{6}(2) is 3^x*2^{1+x}-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=log_{6}(x+2)-log_{6}(2)

inverse

f (x) = lo g_{6} (x + 2) - lo g_{6} (2)

3^{x} \cdot 2^{1 + x} - 2

Solution steps

y = lo g_{6} (x + 2) - lo g_{6} (2)

Replace

x

with

y

x = lo g_{6} (y + 2) - lo g_{6} (2)

Solve for

y, x = lo g_{6} (y + 2) - lo g_{6} (2)

3^{x} \cdot 2^{1 + x} - 2

What is the inverse of f(x)=log_{6}(x+2)-log_{6}(2) ?
The inverse of f(x)=log_{6}(x+2)-log_{6}(2) is 3^x*2^{1+x}-2