What is the inverse of f(x)=\sqrt[3]{x-4}-2 ?

The inverse of f(x)=\sqrt[3]{x-4}-2 is x^3+6x^2+12x+12

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inverse of f(x)=\sqrt[3]{x-4}-2

inverse

f (x) = 3 x - 4 - 2

x^{3} + 6 x^{2} + 12 x + 12

Solution steps

y = 3 x - 4 - 2

Replace

x

with

y

x = 3 y - 4 - 2

Solve for

y, x = 3 y - 4 - 2

x^{3} + 6 x^{2} + 12 x + 12

\frac{x - 1}{( x + 3 ) ( x - 2 )}

\frac{( tan ( x - 1 ) )}{( tan ( x + 1 ) )}

f (x) = arcsin (2 x^{2} - 1)

(1, - 5), (7, 1)

x^{3} - 2 x^{2} - 4 x

What is the inverse of f(x)=\sqrt[3]{x-4}-2 ?
The inverse of f(x)=\sqrt[3]{x-4}-2 is x^3+6x^2+12x+12