What is the perpendicular 3x+2y+3=0 ?

The perpendicular 3x+2y+3=0 is y= 2/3 x+b

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perpendicular 3x+2y+3=0

perpendicular

3 x + 2 y + 3 = 0

y = \frac{2}{3} x + b

Solution steps

Find the slope of

3 x + 2 y + 3 = 0 : m = - \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{3}

Line with slope m=

\frac{2}{3} : y = \frac{2}{3} x + b

y = \frac{2}{3} x + b