f(x)(g(x))f(x)=4x-9,g(x)=((x+4))/9

Lösung

f (x) (g (x)) f (x) = 4 x - 9, g (x) = \frac{( x + 4 )}{9}

\frac{\circ x ^{2} f ( x ) ^{2}}{81} + \frac{8 \circ x f ( x ) ^{2}}{81} + \frac{16 \circ f ( x ) ^{2}}{81}

Schritte zur Lösung

Finde

f (x) (g (x)) f (x) \circ g

gegeben

f (x) (g (x)) f (x) (x) = 4 x - 9, g (x) = \frac{( x + 4 )}{9}

f (x) (g (x)) f (x) \circ g = f (x) (g (x)) f (x) \circ g (x)

g (x) = \frac{( x + 4 )}{9}

g (x) = \frac{( x + 4 )}{9}

= f (x) \frac{x + 4}{9} f (x) \circ \frac{x + 4}{9}

Multipliziere aus

f (x) \frac{x + 4}{9} f (x) \circ \frac{x + 4}{9} : \frac{\circ x ^{2} f ( x ) ^{2}}{81} + \frac{8 \circ x f ( x ) ^{2}}{81} + \frac{16 \circ f ( x ) ^{2}}{81}

= \frac{\circ x ^{2} f ( x ) ^{2}}{81} + \frac{8 \circ x f ( x ) ^{2}}{81} + \frac{16 \circ f ( x ) ^{2}}{81}

g (f) = 101.5 f

p a r i t y f (x) = \frac{x + 12}{x}

f (c) = 98 c

in t erce pt s y - 3 = 5 (x - 2)

s l o p e in t erce pt 2 x - 8 y = 32