extreme x^2-18x+79

解答

极值点

x^{2} - 18 x + 79

极小值 (9, - 2)

求解步骤

f^{'} (x) = 2 x - 18

Find intervals:

递减

: - \infty < x < 9,

递增

: 9 < x < \infty

将

x = 9

代入

x^{2} - 18 x + 79 : - 2

极小值 (9, - 2)

e x t re m e f (x) = 3 x^{4} - 294 x^{2} + 3, - 8 \leq x \leq 8

e x t re m e f (x) = 2 x^{2} - 7, - 7 \leq x \leq 7

e x t re m e x^{2} - 18 x + 86

e x t re m e 2 x^{2} - 4 x + 6

e x t re m e f (x) = 3 (x - e^{x})