What is the extreme f(x)=(x-6)e^{-6x} ?

The extreme f(x)=(x-6)e^{-6x} is Maximum(37/6 , 1/(6e^{37)})

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extreme f(x)=(x-6)e^{-6x}

extreme points

f (x) = (x - 6) e^{- 6 x}

Maximum (\frac{37}{6}, \frac{1}{6 e ^{37}})

Solution steps

f^{'} (x) = - e^{- 6 x} (6 x - 37)

Find intervals:

Increasing

: - \infty < x < \frac{37}{6}

Plug

x = \frac{37}{6}

into

(x - 6) e^{- 6 x} : \frac{1}{6 e ^{37}}

Maximum (\frac{37}{6}, \frac{1}{6 e ^{37}})

2 t^{10} (4 - t^{2})^{5}

f (x) = f (x, y) = - x^{2} - 2 y^{2} + x y + x + 3 y

f (y) = x^{3} + y^{3} - 27 x y

f (x) = - 2 x^{2} + 4 x + 6

f (x) = 12 x^{2} - 88 x + 121

What is the extreme f(x)=(x-6)e^{-6x} ?
The extreme f(x)=(x-6)e^{-6x} is Maximum(37/6 , 1/(6e^{37)})