What is the extreme f(x)=-(x^2)/(10)+2x+3 ?

The extreme f(x)=-(x^2)/(10)+2x+3 is Maximum(10,13)

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extreme f(x)=-(x^2)/(10)+2x+3

extreme points

f (x) = - \frac{x ^{2}}{10} + 2 x + 3

Maximum (10, 13)

Solution steps

f^{'} (x) = - \frac{x}{5} + 2

Find intervals:

Increasing

: - \infty < x < 10,

Decreasing

: 10 < x < \infty

Plug

x = 10

into

- \frac{x ^{2}}{10} + 2 x + 3 : 13

Maximum (10, 13)

f (x) = (x^{3} - 3 x^{2} + 3 x + 1)

f (x) = x^{3} - 3 x + 1, - \frac{3}{2} \leq x \leq 3

16 \cdot x - 4 \cdot ln (x)

f (x, y, z) = 64

f (x) = \frac{16}{x} + 2 π x^{2}

What is the extreme f(x)=-(x^2)/(10)+2x+3 ?
The extreme f(x)=-(x^2)/(10)+2x+3 is Maximum(10,13)