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Beliebt Funktionen >

extreme y=3x^4+16x^3=x^3(3x+16)

Lösung

extrempunkte

y = 3 x^{4} + 16 x^{3} = x^{3} (3 x + 16)

Lösung

Minimum (- 4, - 256), Sattel (0, 0)

Schritte zur Lösung

f^{'} (x) = 12 x^{2} (x + 4)

Intervalle finden:

Absteigend

: - \infty < x < - 4,

Ansteigend

: - 4 < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = - 4

in

x^{3} (3 x + 16) : - 256

Minimum (- 4, - 256)

Stecke

x = 0

in

x^{3} (3 x + 16) : 0

Sattel (0, 0)

Minimum (- 4, - 256), Sattel (0, 0)

Graph

Beliebte Beispiele

extreme f(x)=-4x^3-6x^2+72x+6

e x t re m e f (x) = - 4 x^{3} - 6 x^{2} + 72 x + 6

extreme y=12x^{5/7}+5x^{12/7}

e x t re m e y = 12 x^{\frac{5}{7}} + 5 x^{\frac{12}{7}}

extreme y=x^3-3x^2+7x-10

e x t re m e y = x^{3} - 3 x^{2} + 7 x - 10

extreme f(x)=-10/3 x^3-31/2 x^2-3x+4

e x t re m e f (x) = - \frac{10}{3} x^{3} - \frac{31}{2} x^{2} - 3 x + 4

extreme f(x)=(x^2+7x+13)/(x+4)

e x t re m e f (x) = \frac{x ^{2} + 7 x + 13}{x + 4}