What is the domain of sqrt((-x^2+16)(x+2)) ?

The domain of sqrt((-x^2+16)(x+2)) is x<=-4\lor-2<= x<= 4

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domain of sqrt((-x^2+16)(x+2))

domain

(- x^{2} + 16) (x + 2)

x \leq - 4 or - 2 \leq x \leq 4

Interval Notation

(- \infty, - 4] \cup [- 2, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 2 \leq x \leq 4

The function domain

x \leq - 4 or - 2 \leq x \leq 4

What is the domain of sqrt((-x^2+16)(x+2)) ?
The domain of sqrt((-x^2+16)(x+2)) is x<=-4\lor-2<= x<= 4